Как вытащить значение из словаря JSON?

Пишу на Python. Из словаря в JSON нужно вытащить значение ключа "city". Кусок словаря ниже.
{ "query": { "count": 1, "created": "2018-07-15T13:21:02Z", "lang": "en-US", "results": { "channel": { "units": { "distance": "mi", "pressure": "in", "speed": "mph", "temperature": "F" }, "title": "Yahoo! Weather - Nome, AK, US", "link": "http://us.rd.yahoo.com/dailynews/rss/weather/Country__Country/*https://weather.yahoo.com/country/state/city-2460286/", "description": "Yahoo! Weather for Nome, AK, US", "language": "en-us", "lastBuildDate": "Sun, 15 Jul 2018 05:21 AM AKDT", "ttl": "60", "location": { "city": "Nome", "country": "United States", "region": " AK" }, "wind": { "chill": "50", "direction": "270", "speed": "11" }, "atmosphere": { "humidity": "90", "pressure": "1009.0", "rising": "0", "visibility": "14.9" }, "astronomy": { "sunrise": "1:4 am", "sunset": "5:9 am" }, "image": { "title": "Yahoo! Weather", "width": "142", "height": "18", "link": "http://weather.yahoo.com", "url": "http://l.yimg.com/a/i/brand/purplelogo//uh/us/news-wea.gif" }, "item": { "title": "Conditions for Nome, AK, US at 03:00 AM AKDT", "lat": "64.499474", "long": "-165.405792", "link": "http://us.rd.yahoo.com/dailynews/rss/weather/Country__Country/*https://weather.yahoo.com/country/state/city-2460286/", "pubDate": "Sun, 15 Jul 2018 03:00 AM AKDT", "condition": { "code": "26", "date": "Sun, 15 Jul 2018 03:00 AM AKDT", "temp": "52", "text": "Cloudy" }, "forecast": [ { "code": "11", "date": "15 Jul 2018", "day": "Sun", "high": "53", "low": "49", "text": "Showers" },
Значение ключа "count" вывести получается:
response = requests.get(url).json() print(response["query"]["count"])
А вот то, что дальше не знаю как оформить, подскажите, пожалуйста.

Ответ

Воспользуйтесь модулем dpath
In [193]: import dpath # pip install dpath
In [194]: dpath.util.search(response, '**/city') Out[194]: {'query': {'results': {'channel': {'location': {'city': 'Nome'}}}}}
In [199]: dpath.util.values(response, '**/city') Out[199]: ['Nome']
In [200]: dpath.util.get(response, '/query/results/channel/location/city') Out[200]: 'Nome'
PS пример валидного JSON response...
In [201]: url = 'https://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20weather.forecast%20where%20woeid%20in%20(select%20woeid%20from%20geo.places(1)%20where%20text%3D%22munich%2C%20germany%22)&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys'
In [202]: import requests
In [203]: response = requests.get(url).json()
In [204]: dpath.util.get(response, '/query/results/channel/location/city') Out[204]: 'Munich'
In [205]: dpath.util.values(response, '**/city') Out[205]: ['Munich']
In [206]: dpath.util.search(response, '**/city') Out[206]: {'query': {'results': {'channel': {'location': {'city': 'Munich'}}}}}
In [207]: dpath.util.get(response, '/query/results/channel/location') Out[207]: {'city': 'Munich', 'country': 'Germany', 'region': ' BY'}