Проблема с прокручиванием большого количества элементов в ListView

Есть ListView в котором есть 1000 элементов и при быстрой прокрутке списка возникает эффект как у колеса машины, сначала в одну сторону прокрутка идет , а потом обратно, хотя по факту он в нужную сторону крутится, каким образом можно избавиться от этого эффекта? Возможно для большого количества элементов в списке нужен другой адаптер ?
ListViewAdapter.java
public class ContactListAdapter extends BaseAdapter {
private Context context; private static final String TAG = "ContactListAdapter";
ArrayList list; private LayoutInflater layoutInflater;
private ViewHolder preHolder; private ViewHolder secondHold;
public ContactListAdapter(Context context, ContactList contactList) { this.context = context; list = contactList; layoutInflater = (LayoutInflater) this.context.getSystemService(Context.LAYOUT_INFLATER_SERVICE); }
public void setList(ArrayList list) { this.list = list; }
public static class ViewHolder { private View rootView; private TextView tvName; private TextView tvInitials; private ImageView ivAvatart; private ImageView ivStatus;
private RelativeLayout relativeLayoutParent; private RelativeLayout relativeLayoutMain; private RelativeLayout onlineButtonContainer; private RelativeLayout timeoutButtonContainer; private RelativeLayout relativeLayout_exit_buuton_conteiner; private RelativeLayout relativeLayout_icon_phone; private String contactName; private boolean isShow;
private ContactCaling contactCaling; }
@Override public View getView(final int position, final View convertView, final ViewGroup parent) {
final ViewHolder holder;
if (convertView == null) { holder = new ViewHolder(); holder.rootView = convertView;
LayoutInflater layoutInflater = (LayoutInflater) context .getSystemService(Context.LAYOUT_INFLATER_SERVICE); holder.rootView = layoutInflater.inflate(R.layout.main_contact_list_item, null);
holder.tvName = (TextView) holder.rootView.findViewById(R.id.textView_contact_name); holder.tvInitials = (TextView) holder.rootView.findViewById(R.id.textView_contact_initials); holder.ivAvatart = (ImageView) holder.rootView.findViewById(R.id.imageView_contact_avatar); holder.ivStatus = (ImageView) holder.rootView.findViewById(R.id.imageView_status); holder.relativeLayoutParent = (RelativeLayout) holder.rootView.findViewById(R.id.relativeLayout_parent); holder.relativeLayoutMain = (RelativeLayout) holder.rootView.findViewById(R.id.relativeLayout_main); holder.onlineButtonContainer = (RelativeLayout) holder.rootView.findViewById(R.id.relativeLayout_call_button_container); holder.relativeLayout_icon_phone = (RelativeLayout) holder.rootView.findViewById(R.id.relativeLayout_icon_phone); holder.timeoutButtonContainer = (RelativeLayout) holder.rootView.findViewById(R.id.relativeLayout_call_busy_button_container); holder.relativeLayout_exit_buuton_conteiner = (RelativeLayout) holder.rootView.findViewById(R.id.relativeLayout_exit_buuton_conteiner);
/**-------------Item listener---------------**/
holder.relativeLayoutParent.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { if (preHolder == null || (secondHold != null && secondHold.equals(holder))) { if (MyApplication.isOnline()) { int buttonTranslation = -holder.onlineButtonContainer.getLayoutParams().width + 2;
holder.onlineButtonContainer .animate() .translationX(buttonTranslation) .setDuration(350); secondHold = null; } else { int buttonTranslation = -holder.timeoutButtonContainer.getLayoutParams().width + 2;
holder.timeoutButtonContainer .animate() .translationX(buttonTranslation) .setDuration(350); secondHold = null; }
}
if (preHolder != null) {
if (MyApplication.isOnline()) { int translate = preHolder.onlineButtonContainer.getLayoutParams().width; preHolder.relativeLayoutMain .animate() .translationX(0) .setDuration(350); preHolder.onlineButtonContainer .animate() .translationX(translate) .setDuration(350); } else { int translate = preHolder.timeoutButtonContainer.getLayoutParams().width; preHolder.relativeLayoutMain .animate() .translationX(0) .setDuration(350); preHolder.timeoutButtonContainer .animate() .translationX(translate) .setDuration(350); }
}
if (preHolder != null) { preHolder = null; } else { preHolder = holder; } secondHold = holder; }
});
holder.isShow = false; holder.rootView.setTag(holder); } else { holder = (ViewHolder) convertView.getTag(); }
holder.contact = (Contact) getItem(position); holder.contactName = holder.contact.getDisplayName();
holder.tvName.setText(holder.contactName); setIcons(position, holder);
return holder.rootView; }
@Override public int getCount() { return list.size(); }
@Override public Object getItem(int position) { return list.get(position); }
@Override public long getItemId(int position) { return position; } }

Ответ

Нужно сделать так, что бы частота обновления экрана была различна с частотой прокручивания элементов списка. Наверно можно уменьшить скорость скрола ListView
listView.setFriction(ViewConfiguration.getScrollFriction() * FRICTION_SCALE_FACTOR)